I assume it's 3 x − 12 = 0
[\sqrt{3x-12}=0\ 3x-12=0\ 3x=12\ x=4
]
√3x - 12 = 0
√3x = 12
(√3x)^2 = (12)^2
3x = 144
x = 48
To solve the equation 3 x − 12 = 0 , we isolate the square root, square both sides, and solve for x . The solution is x = 48 , which can be verified by substituting it back into the original equation.
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