Need help: Solve for y.

Try factoring first; if not possible or difficult, use the quadratic formula.

\[ y^2 - 6y + 6 = 0 \]

y 2 − 6 y + 6 = 0 a = 1 , b = − 6 , c = 6 Δ = b 2 − 4 a c = ( − 6 ) 2 − 4 ⋅ 1 ⋅ 6 = 36 − 24 = 12 Δ ​ = 12 ​ = 4 ⋅ 3 ​ = 2 3 ​ x 1 ​ = 2 a − b − Δ ​ ​ = 2 6 − 2 3 ​ ​ = 2 2 ( 3 − 3 ​ ) ​ = 3 − 3 ​
x 2 ​ = 2 a − b + Δ ​ ​ = 2 6 + 2 3 ​ ​ = 2 2 ( 3 + 3 ​ ) ​ = 3 + 3 ​

Answered by Lilith | 2024-06-10

y 2 − 6 y + 6 = 0 y 2 − 6 y + 9 − 3 = 0 ( y − 3 ) 2 = 3 ∣ y − 3∣ = 3 ​ y − 3 = 3 ​ ∨ y − 3 = − 3 ​ y = 3 + 3 ​ ∨ y = 3 − 3 ​

Answered by konrad509 | 2024-06-10

The solutions for the equation y 2 − 6 y + 6 = 0 are y = 3 − 3 ​ and y = 3 + 3 ​ . We used the quadratic formula to find these values since factoring was not straightforward. This process involved calculating the discriminant and applying it in the quadratic formula.
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Answered by Lilith | 2025-01-30