Eighteen people ordered soup and sandwiches for lunch. Sandwiches cost $7.75 each, and the soup costs $4.50 each. The total cost of the lunch was $113.50. How many sandwiches were ordered?

Let the soup be x and sandwich be y 7.75x+4.50y=113.50 x=18-y 7.75(18-y)+4.50y=113.50 y=10 x+y=18 so x=8

Answered by venkatraya | 2024-06-10

Let soups be represented by x and sandwiches by y.
x + y = 18 4.5x + 7.75y = 113.50
x = 18 - y
4.5(18 -y) + 7.75 y = 113.5
= 81 - 4.5y + 7.75y = 113.5
81 + 3.25y = 113.5
3.25y = 32.5
y = 10.
x + y = 18 x + 10 = 18
Thus, x = 8.
Thus, 8 soups and 10 sandwiches were ordered.

Answered by tadvisohil886 | 2024-06-10

A total of 10 sandwiches were ordered. Using a system of equations, we determined this by setting up relationships for the total items and costs. The remaining items, 8, were soup bowls, which also satisfied the cost condition.
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Answered by venkatraya | 2025-01-14