The function [tex]f(t) = -5t^2 + 20t + 60[/tex] models the approximate height of an object \( t \) seconds after it is launched. How many seconds does it take the object to hit the ground?

f(t) = -5t^2 + 20t + 60 -5(t^2 - 4t - 12) -5(t + 2) (t - 6) t = -2 or t = 6
6 seconds

Answered by kayt91 | 2024-06-10

6 seconds. ;

Answered by ApusApus | 2024-06-25

The object takes 6 seconds to hit the ground as determined by solving the equation derived from its height function. The quadratic equation yields time values of 6 and -2 seconds, where only 6 seconds is valid. Therefore, the object hits the ground at 6 seconds after launch.
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Answered by ApusApus | 2024-09-05