[y^2-10y+23=0\ y^2-10y+25-2=0\ (y-5)^2=2\ |y-5|=\sqrt2\ y-5=\sqrt 2 \vee y-5=-\sqrt2\ y=5+\sqrt2 \vee y=5-\sqrt2
]
To solve the equation y 2 − 10 y + 23 = 0 , we used the quadratic formula. The solutions are y = 5 + 2 and y = 5 − 2 . Since the discriminant is positive, there are two distinct real solutions.
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