Which point lies on the graph of the boundary line of the inequality [tex]3y + 4x < 12[/tex]?

3 y + 4 x < 12 3 y < − 4 x + 12 / : 3 y < − 3 4 ​ x + 4

Answered by Lilith | 2024-06-10

To find a point on the boundary line of the inequality 3 y + 4 x < 12 , we set the equation to 3 y + 4 x = 12 and solve for y . This gives us the boundary line y = − 3 4 ​ x + 4 . Examples of points on this line include (0, 4) and (3, 0).
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Answered by Lilith | 2024-10-02