What's the equation of a circle centered at (7,1) that passes through (-2,10)?
Answer (2)
The line from (7, 1) to (-2 10) is a radius of the circle.
Its length is the square root of [ (-2 - 7)² + (10 - 1)² ] = √(81 + 81) = √162
The equation of the circle is: **(x- 7)² + (y - 1)² = 162 **
The equation of the circle centered at (7, 1) that passes through the point (-2, 10) is given by (x - 7)² + (y - 1)² = 162. This is derived by calculating the radius using the distance formula. The final equation represents the set of all points at this distance from the center.
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