What are the possible values for x in the equation \(4x^2 = 64\)?

1. \(x = 0\)
2. \(x = 4\)
3. \(x = 4, -4\)
4. \(x = 0, 4, -4\)

4x^2 = 64

4(0^2) = 64 4(0) = 64 0 = 64 Not True

4(4^2) = 64 4(16) = 64 64 = 64 True

4(4^2) = 64 4(16) = 64 64 = 64 4(-4^2) = 64 4(16) = 64 64 = 64 True

4(4^2) = 64 4(16) = 64 64 = 64 4(-4^2) = 64 4(16) = 64 64 = 64 4(0^2) = 64 4(0) = 64 0 = 64 Not True


Answer: (3)

Answered by iloveonedirection | 2024-06-10

4 x 2 = 64 / : 4 x 2 = 16 x 2 − 16 = 0 x 2 − 4 2 = 0 ( x − 4 ) ( x + 4 ) = 0 x − 4 = 0 or x + 4 = 0 x = 4 or x = − 4 A n s w er : ( 3 )

Answered by Lilith | 2024-06-10

The possible values for x in the equation 4 x 2 = 64 are 4 and − 4 . Therefore, the correct answer is option 3: x = 4 , − 4 . This is because we derived these solutions from simplifying the equation and taking the square roots of both sides.
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Answered by iloveonedirection | 2024-12-24