The area of a square field is 60025 m². A man cycles along its boundary at 18 km per hour.

In how much time will he return to the starting point?

Area=60025\ m^2\ \ \ and\ \ \ Area=a^2\\\\\ \ \ \Rightarrow\ \ \ a^2=60025\ m^2 \ \ \Rightarrow\ \ \ a=245\ m\\\\\ \Rightarrow\ \ \ the\ perimeter\ of\ a\ square:\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ P=4a=4\cdot245\ m=980\ m=0.98\ km\\\\ Speed=18 \frac{km}{h} \ \ \ and\ \ \ Speed= \frac{\big{P}}{\big{time}} \\\\18= \frac{\big{0.98}}{\big{time}}\\\\\ \ \ \Rightarrow \ \ \ time= \frac{\big{0.98}}{\big{18}}\ hr=\frac{\big{0.98}}{\big{18}}\ \cdot3660\ s=196\ s=3\ min\ 16\ s\\
A n s . h e w i ll re t u r n a f t er 3 min u t es 16 seco n d s .

Answered by kate200468 | 2024-06-10

Area of square field = 60025 m
Thus, side = √60025 = 245 m.
Perimeter = 245 * 4 = 980 meters
Speed = 18 kmph = 5m/s
Time = Distance / speed
= 980 / 5
= 196.
Thus, it will take 196 seconds for the man to return at the starting point.

Answered by tadvisohil886 | 2024-06-10

The man will take 3 minutes and 16 seconds to return to the starting point after cycling around the square field. This time is calculated using the perimeter of the square and his cycling speed. The perimeter is 980 m, and cycling at a speed of 18 km/h (or 5 m/s) determines the total time taken.
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Answered by kate200468 | 2024-12-26