I need help with this equation:

\[ x^2 + y^2 - 4x - 6x + 9 = 0 \]

x 2 + y 2 − 4 x − 6 y + 9 = 0 x 2 − 4 x + 16 + y 2 − 6 y + 9 − 16 = 0 ( x − 4 ) 2 + ( y − 3 ) 2 = 16 t hi s i s t h e e q u a t i o n o f a c i rc l e : ( x − a ) 2 + ( y − b ) 2 = r 2 ce n t er S = ( 4 ; 3 ) an d r a d i u s r = 4

Answered by kate200468 | 2024-06-10

By completing the square, the equation x 2 + y 2 − 4 x − 6 y + 9 = 0 is transformed into the standard form of a circle, ( x − 2 ) 2 + ( y − 3 ) 2 = 4 . The circle has its center at ( 2 , 3 ) and a radius of 2. This process involves rearranging and completing the square for both x and y .
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Answered by kate200468 | 2025-06-12