Find the y-intercept(s), if any, for the equation \(y = x^2 - 16\).

t h e y − in t erce pt : y = x 2 − 16 an d x = 0 ⇒ y = 0 2 − 16 = − 16

Answered by kate200468 | 2024-06-10

if you follow the **y=mx+b form **m is always your slope and **b is always your y-intercept **so since this equation is in that form then you can see that 16 is your y-intercept! Since it is at the end of the equation, because if its in that proper form then your last number is always your "b" (in other words, the last number is always the y-interept in every equation like that)
Hope I helped you:)

Answered by Greenbubblelove | 2024-06-10

The y-intercept of the equation y = x 2 − 16 is − 16 . This means that when x = 0 , y equals − 16 , leading to the point ( 0 , − 16 ) where the graph intersects the y-axis.
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Answered by kate200468 | 2024-12-23