Use substitution to solve the system of equations:

\[ x = 3y + 7 \]

\[ 3x - 4y = 16 \]

x = 3y + 7 3x - 4y = 16
Substituting the value of x,
3(3y + 7) - 4y = 16
9y + 21 - 4y = 16
5y + 21 = 16
5y = -5
Thus, y = -1.
Substituting the value of y,
x = 3y + 7
x = -3 + 7
Thus, x = 4.
Thus, x = 4, and y = -1

Answered by tadvisohil886 | 2024-06-10

First we already know x, so we can put it into the other equation like so:
3(3y+7)-4y=16
Then we can solve it.
9y+21-4y=16
5y=-5
y=-1
Then we can find x.
x=3y+7
x=3(-1)+7
x=-3+7
x=4
Hope I helped!

Answered by Anonymous | 2024-06-24

The solutions to the system of equations are x = 4 and y = − 1 . To find these values, we substituted x from the first equation into the second equation and solved for y . Then, we substituted back to find x .
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Answered by Anonymous | 2024-11-01