Write the equation of the line that passes through (2, 3) and is parallel to the line [tex]12x – 5y = 2[/tex].

k : 12 x − 5 y = 2 → − 5 y = − 12 x + 2 / : ( − 5 ) → y = 5 12 ​ y − 5 2 ​ l : y = m x + b k ∣∣ l ⟺ m = 5 12 ​ l : y = 5 12 ​ x + b ; ( 2 ; 3 ) 5 12 ​ ⋅ 2 + b = 3 5 24 ​ + b = 3 b = 5 15 ​ − 5 24 ​ b = − 5 9 ​ A n s w er : y = 5 12 ​ x − 5 9 ​ → 5 12 ​ x − y = 5 9 ​ / ⋅ 5 → 12 x − 5 y = 9

Answered by Anonymous | 2024-06-10

The equation of the line parallel to 12 x − 5 y = 2 and passing through the point ( 2 , 3 ) is y = 5 12 ​ x − 5 9 ​ , or in standard form, 12 x − 5 y = 9 .
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Answered by Anonymous | 2024-09-19