Find the intercepts of the equation \(9x^2 + 9y = 81\).
Answer (2)
x = 0 9 x 2 + 9 y = 81 9. 0 2 + 9 y = 81 9 y = 81 y = 9 81 y = 9
y = 0 9 x 2 + 9.0 = 81 9 x 2 = 81 x 2 = 9 81 x 2 = 9 x = ± 3
The intercepts of the equation 9 x 2 + 9 y = 81 are found by setting x and y to zero. The y-intercept is ( 0 , 9 ) and the x-intercepts are ( 3 , 0 ) and ( − 3 , 0 ) . Thus, the intercept points are ( 0 , 9 ) , ( 3 , 0 ) , and ( − 3 , 0 ) .
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