Find the 5th term of the sequence defined as:
\[ a(n) = (n+3)^{n-1} \]
Answer (2)
a n = ( n + 3 ) n − 1 a 1 = ( 1 + 3 ) 1 − 1 = 4 − 1 = 3 a 2 = ( 2 + 3 ) 2 − 1 = 5 2 − 1 = 25 − 1 = 24 a 3 = ( 3 + 3 ) 3 − 1 = 6 3 − 1 = 216 − 1 = 215 a 4 = ( 4 + 3 ) 4 − 1 = 7 4 − 1 = 2401 − 1 = 2400 a 5 = ( 5 + 3 ) 5 − 1 = 8 5 − 1 = 32768 − 1 = 32767
The 5th term of the sequence defined by a ( n ) = ( n + 3 ) n − 1 is 4096. This was found by evaluating the expression for n = 5 .
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