What is the diagonal of a rectangle with a length of 48 inches and a width of 40 inches?

Use the Pythagorean Theorem: a 2 + b 2 = c 2 You can do this because when you cut the rectangle in half with the diagonal, it forms a right triangle, making the diagonal the hypotenuse (c).
4 0 2 + 4 8 2 = c 2
1600 + 2304 = c 2
3904 = c 2
3904 ​ = c 2 ​
62.48 = c
Diagonal: 62.48 inches

Answered by iloveonedirection | 2024-06-10

i think its D =w 2 + l2 = 402 + 482 ≈ 62.482 in

Answered by arnav1 | 2024-06-10

The diagonal of a rectangle with a length of 48 inches and a width of 40 inches can be found using the Pythagorean Theorem. The diagonal is approximately 62.48 inches. This is determined by calculating the square root of the sum of the squares of the length and width.
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Answered by iloveonedirection | 2024-12-24