In how many ways can a committee of 6 be chosen from 5 teachers and 4 students if the committee must include 3 teachers and 3 students?

[5! / 3! * 2!] *[4! / 3! * 1!] = ( 20 / 2 ) * 4 = 40 ways;

Answered by crisforp | 2024-06-10

The number of ways to form a committee of 6 consisting of 3 teachers and 3 students from 5 teachers and 4 students is 40. This is calculated by multiplying the ways to choose the teachers (10) by the ways to choose the students (4). Thus, the total is 40 ways.
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Answered by crisforp | 2024-12-24