Solve the equation by factoring:

\[ 6k^2 + 21 = 27k \]

6 k 2 + 21 = 27 k 6 k 2 − 27 k + 21 = 0 3 ( 2 k 2 − 9 k + 7 ) = 0 3 ( 2 k 2 − 2 k − 7 k + 7 ) = 0 3 [ 2 k ( k − 1 ) − 7 ( k − 1 )] = 0 3 ( k − 1 ) ( 2 k − 7 ) = 0 ⇔ k = 1 or k = 3.5

Answered by kate200468 | 2024-06-10

(3k+7)(3k-3) is the answer. Subtract 27k from each side to get 6k2-27k+21, and then factor through

Answered by Velez152 | 2024-06-10

To solve the quadratic equation 6 k 2 + 21 = 27 k , we rearranged it to 6 k 2 − 27 k + 21 = 0 and factored it to get ( 3 k − 7 ) ( 2 k − 3 ) = 0 . The solutions are k = 3 7 ​ and k = 2 3 ​ .
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Answered by kate200468 | 2024-12-24