You fill up a 40-gallon pool by putting in 2 gallons of water every minute. If someone scoops out 1 gallon every 8 minutes, how long would it take to fill the pool?

Question

AL2006 · Answer

There's a catch here, and I don't really want to go into full detail. Because of this catch, I think it would be unusually tough to write a simple equation for this situation. If you wouldn't mind, let's just list it instead: 
 After . . water added . . total in pool 
 7 min . . . 14 gallons . . . 14 gallons 1 more . . 1 gallon . . . . . 15 gallons 7 more . . 14 gallons . . . 29 gallons 1 more . . 1 gallon . . . . . 30 gallons 5 more . . 10 gallons . . . 40 gallons, the pool is full 
 Add up all the minutes: 21 minutes

dandann · Answer

It would take 21 minutes As the first 8 minutes there would be 15 gallons in the pool In 16 minutes there would be 30 gallons in the pool Therefore you only need 10 gallons left which will be filled up in the space of 5 minutes

Answered by dandann | 2024-06-10

AL2006 · Answer

It will take approximately 21.33 minutes to fill a 40-gallon pool with 2 gallons of water being added every minute while 1 gallon is being scooped out every 8 minutes. This results in a net inflow of 1.875 gallons per minute. Therefore, the calculation gives us the total time needed to fill the pool. 
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You fill up a 40-gallon pool by putting in 2 gallons of water every minute. If someone scoops out 1 gallon every 8 minutes, how long would it take to fill the pool?

Answer (3)

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