What is the period of the function \( y = \frac{1}{2} \sec \theta \)? Please explain how you found your answer.

I'm not too sure of what the secant looks like on a graph, but I know that the secant is (1 / the cosine), and I'm very familiar with the cosine.
The period of the cosine is 360 degrees, or 2π radians, so that's the period of the secant.
That (1 / 2) in the equation only affects the amplitude, not the period.

Answered by AL2006 | 2024-06-10

The period of the function y = 2 1 ​ sec θ is 2 π radians. This is because the secant function shares the same period as the cosine function, which is 36 0 ∘ or 2 π radians. The coefficient 2 1 ​ only affects the amplitude, not the period.
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Answered by AL2006 | 2024-12-23