Standing in your tree house, 50 feet off the ground, you look down at a 60° angle and notice a Frisbee. Approximately how many feet from the base of the tree is the Frisbee?

α = 6 0 o , b = 50 f ee t t an α = a b ​ t an 6 0 o = 50 b ​ 3 ​ = 50 b ​ / ⋅ 50 b = 50 3 ​ ≈ 50 ⋅ 1.73 = 86.5 f ee t A n s w er : F r i s b ee i s ab o u t 50 f ee t f ro m t h e ba se o f t h e t ree

Answered by Lilith | 2024-06-10

Using trigonometry, we determined that the Frisbee is approximately 28.87 feet from the base of the tree, based on a 60° angle of depression and a height of 50 feet. This was calculated using the tangent function to relate the height and distance. Therefore, the final answer is around 28.87 feet away.
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Answered by Lilith | 2024-12-24