How do you factor \( y = 6x^2 + 24x - 192 \) and find the zeros?

y = 6 x 2 + 24 x − 192 y = 0 ⇔ 6 x 2 + 24 x − 192 = 0 / : 6 x 2 + 4 x − 27 = 0 x 2 + 2 ⋅ 2 ⋅ x + 2 2 − 2 2 − 27 = 0 ( x + 2 ) 2 − 31 = 0 ( x + 2 ) 2 = 31 ⇔ ( x + 2 = 31 ​ or x + 2 = − 31 ​ ) x = − 2 + 31 ​ or x = − 2 − 31 ​

Answered by kate200468 | 2024-06-10

To factor the equation y = 6 x 2 + 24 x − 192 , we simplify it to ( x + 8 ) ( x − 4 ) = 0 . The zeros are x = − 8 and x = 4 .
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Answered by kate200468 | 2024-12-19