A bag contains 12 slips of paper of the same size. Each slip has one number on it, from 1 to 12.

Describe an impossible event.

There are many impossible events. Here are a few. I'm sure you can think of at least 15 more:
-- Pull 5 multiples of 3 from the bag.
-- Pull 3 multiples of 5 from the bag.
-- Pull 7 odd numbers from the bag.
-- Pull 7 even numbers from the bag.
-- Pull two slips from the bag whose sum is more than 21 .
-- Pull three slips from the bag whose sum is more than 33 .
-- Pull two slips from the bag whose sum is less than 3 .
-- Pull three slips from the bag whose sum is less than 6 .
-- Pull two slips from the bag whose product is more than 132 .
-- Pull two slips from the bag whose product is less than 2 .
etc.

Answered by AL2006 | 2024-06-10

An impossible event in this scenario includes pulling a slip with a number that does not exist in the bag, such as 13 or any negative number. Other impossible events could involve combinations of numbers that cannot yield the stated results. Specifically, events must be rooted in the constraints of the items present in the bag, which contains numbers only from 1 to 12.
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Answered by AL2006 | 2024-12-26