g − a = g s g − g s = a g ( 1 − s ) = a / : ( 1 − s ) an d s = 1 g = 1 − s a
I think the equation is:
-a = g s
Divide each side by 's':
-a/s = g
To solve for g in the equation − a = g s , we divide both sides by s to isolate g . The final solution is g = s − a . This indicates that g is inversely proportional to s .
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