E k = 2 1 m . v 2 E k = 2 1 .3 ∗ 2 0 2 E k = 2 1 ∗ 3 ∗ 400 E k = 600 J
The kinetic energy of a 3-kilogram ball rolling at 2 meters per second is 6 Joules (J). This is calculated using the formula K E = 2 1 m v 2 . By substituting the values given, we arrive at the final answer of 6 J.
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