The school hall is 4 times as long as it is wide. If the perimeter is 55m, what are the length and the width?

-- The width of the school is ' W '. We don't know what that is yet, but we're going to find out.
-- We're told that the length is 4 times as much. So the length is ' 4 W '.
-- Perimeter is (2 widths) + (2 lengths).
2 widths = 2 W 2 lengths = 8 W Perimeter = 10 W
-- We're also told that the perimeter is 55m. That's just what we need.
10 W = 55 m
Divide each side of this equation by 10:
W = 5.5 m
There's the width !
The length of the hall is 4 times as much.
Length = 4 W = 22 m

Answered by AL2006 | 2024-06-10

The width of the school hall is 5.5 meters, and the length is 22 meters, as the length is four times the width. By using the perimeter formula and substituting known values, we solved for both dimensions. Thus, the dimensions of the hall meet the given conditions.
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Answered by AL2006 | 2024-09-26