Find the solution to the following equation by transforming it into a perfect square trinomial.

\[ x^2 + 2x = 8 \]

x 2 + 2 x = 8 a dd 1 t o b o t h s i d es x 2 + x + 8 + 1 in t h e l e f t s i d e yo u f in d a p er f ec t s q u a re t r in o mia l ( x + 1 ) 2 = 9 S o : x + 1 = ± 9 ​ x + 1 = ± 3 x + 1 = 3 → x = 2 x + 1 = − 3 → \x = − 4

Answered by Ryan2 | 2024-06-10

x2+2x-8 =0 x2 + 4x - 2x - 8 = 0 x(x+4) - 2(x+4) = 0 (x-2)(x+4) = 0 let x- 2 = 0 x = 2 let x+4 = 0 x= -4

Answered by soniaagarwal09 | 2024-06-10

To find solutions to the equation x 2 + 2 x = 8 , we rearranged it to ( x + 1 ) 2 = 9 and then solved for x resulting in two solutions: x = 2 and x = − 4 .
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Answered by Ryan2 | 2024-09-30