Use the quadratic formula to solve [tex]2y^2 - 10y + 8 = 0[/tex].
Answer (2)
2 y 2 − 10 y + 8 = 0 a = 2 , b = − 10 , c = 8 Δ = b 2 − 4 a c = ( − 10 ) 2 − 4 ⋅ 2 ⋅ 8 = 100 − 64 = 36 x 1 = 2 a − b − Δ = 2 ⋅ 2 10 − 36 = 4 10 − 6 = 4 4 = 1 x 2 = 2 a − b + Δ = 2 ⋅ 2 10 + 36 = 4 10 + 6 = 4 16 = 4
The quadratic equation 2 y 2 − 10 y + 8 = 0 can be solved using the quadratic formula. The two solutions are y = 1 and y = 4 . This was determined by calculating the discriminant and applying the quadratic formula.
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