Use the quadratic formula to solve [tex]2y^2 - 5y = -2[/tex].

2 y 2 − 5 y = − 2 / + 2 2 y 2 − 5 y + 2 = 0 a = 2 ; b = − 5 ; c = 2 Δ = b 2 − 4 a c Δ = ( − 5 ) 2 − 4 ⋅ 2 ⋅ 2 = 25 − 16 = 9 y 1 ​ = 2 a − b − Δ ​ ​ ; y 2 ​ = 2 a − b + Δ ​ ​ Δ ​ = 9 ​ = 3 y 1 ​ = 2 ⋅ 2 5 − 3 ​ = 4 2 ​ = 2 1 ​ ; y 2 ​ = 2 ⋅ 2 5 + 3 ​ = 4 8 ​ = 2

Answered by Anonymous | 2024-06-10

The **solution **of the **quadratic **equation 2y² - 5y = - 2 are,
x = 2
And x = 1/2
Given that,
The quadratic **equation **is,
2y² - 5y = - 2
To find the **solution **to the quadratic equation, use the quadratic **formula **to simplify the equation, which is,
The root of the equation a x 2 + b x + c = 0 , is,
x = 2 a − b ± b 2 − 4 a c ​ ​
The quadratic equation is,
2 y 2 − 5 y = − 2
2 y 2 − 5 y + 2 = 0
Here, a = 2
b = - 5
c = 2
Substitute all the values in the **quadratic **formula,
x = 2 × 2 − ( − 5 ) ± ( − 5 ) 2 − 4 × 2 × 2 ​ ​
x = 4 5 ± 25 − 16 ​ ​
x = 4 5 ± 9 ​ ​
x = 4 5 ± 3 ​
It gives two solutions,
x = 4 5 + 3 ​
x = 4 8 ​
x = 2
And, x = 4 5 − 3 ​
x = 4 2 ​
x = 2 1 ​
So, the **solutions **are,
x = 2
x = 2 1 ​
To learn more about the quadratic equation visit:
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Answered by alifaijal77 | 2024-06-18

To solve 2 y 2 − 5 y = − 2 using the quadratic formula, we rearranged it to 2 y 2 − 5 y + 2 = 0 with a = 2 , b = − 5 , and c = 2 . Applying the quadratic formula gives two solutions: y = 2 and y = 2 1 ​ .
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Answered by alifaijal77 | 2024-12-23