How do you solve \(2x^2 - 32 = 0\) using square roots?

2 x 2 − 32 = 0 2 ( x 2 − 16 ) = 0 / : x 2 − 16 = 0 x 2 − 4 2 = 0 ( x − 4 ) ( x + 4 ) = 0 x − 4 = 0 or x + 4 = 0 x = 4 x = − 4

Answered by kate200468 | 2024-06-10

2 x 2 − 32 = 0 / : 2 x 2 − 16 = 0 x 2 − 4 2 = 0 ( x − 4 ) ( x + 4 ) = 0 x − 4 = 0 or x + 4 = 0 x = 4 or x = − 4

Answered by Lilith | 2024-06-10

To solve 2 x 2 − 32 = 0 , first, isolate x 2 by dividing by 2 to get x 2 = 16 . Then take the square root to find the solutions x = 4 and x = − 4 .
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Answered by kate200468 | 2024-12-24