Can you solve [tex]64x^3 + y^3[/tex] by factoring?

a 3 + b 3 = ( a + b ) ( a 2 − ab + b 2 ) − − − − − − − − − − − − − − − − − 64 x 3 + y 3 = ( 4 x ) 3 + y 3 = ( 4 x + y ) [( 4 x ) 2 − 4 x ⋅ y + y 2 ] = = ( 4 x + y ) ( 16 x 2 − 4 x y + y 2 )

Answered by kate200468 | 2024-06-10

64 x 3 + y 3 = ( 4 x ) 3 + y 3 = ( 4 x + y ) [( 4 x ) 2 − 4 x y + y 2 ] = ( 4 x + y ) ( 16 x 2 − 4 x y + y 2 )

Answered by Anonymous | 2024-06-24

To factor 64 x 3 + y 3 , we can use the sum of cubes formula. The expression factors into ( 4 x + y ) ( 16 x 2 − 4 x y + y 2 ) . This follows from identifying the terms as cubes and applying the appropriate formula.
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Answered by kate200468 | 2024-10-02