Multiply the polynomials:

\((3m - 1)(8m + 7)\)

( 3 m − 1 ) ( 8 m + 7 ) = 3 m ⋅ 8 m + 3 m ⋅ 7 − 1 ⋅ 8 m − 1 ⋅ 7 = = 24 m 2 + 21 m − 8 m − 7 = 24 m 2 + 13 m − 7

Answered by Lilith | 2024-06-10

The product of (3m-1)(8m+7) is 24m² + 13m - 7.
To multiply the polynomials (3m-1)(8m+7), we can use the distributive property. We multiply each term in the first polynomial by each term in the second polynomial and then combine like terms.
(3m-1)(8m+7) = 3m(8m) + 3m(7) - 1(8m) - 1(7)
Simplifying this expression, we get:
24m² + 21m - 8m - 7
Combining like terms, we have:
24m² + 13m - 7
Therefore, the product of (3m-1)(8m+7) is 24m² + 13m - 7.
We can also see that this product represents a quadratic polynomial. The highest power of the variable "m" is 2, which is indicated by the term 24m². The other terms, 13m and -7, represent the linear and constant parts of the polynomial, respectively.
The result is a quadratic polynomial in standard form, where the terms are arranged in descending order of the variable's exponent. In this case, the quadratic polynomial is 24m² + 13m - 7.
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Answered by rachanavt02 | 2024-06-17

To multiply the polynomials ( 3 m − 1 ) ( 8 m + 7 ) , we apply the distributive property, resulting in 24 m 2 + 13 m − 7 . This quadratic polynomial consists of a leading term, a linear term, and a constant. The final product can be expressed as 24 m 2 + 13 m − 7 .
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Answered by rachanavt02 | 2024-11-02