Find two consecutive integers such that the larger is nine more than twice the smaller.

First integer: n Second integer: n+1 (n+1)=2(n)+9 n-8=2n -8=n -8=n -7=n+1 The two consecutive integers would be -8 and -7

Answered by ch33zymanjow | 2024-06-10

The two consecutive integers are -8 and -7. The smaller integer is -8 and the larger is -7. The larger integer is nine more than twice the smaller integer.
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Answered by ch33zymanjow | 2024-10-02