Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 hours, and Car B traveled the distance in 1.5 hours. Car B traveled 15 mph faster than Car A.
How fast did Car B travel?
Answer (2)
d = v ⋅ t d - distance v - speed t - time
Car A: v 1 t 1 = 2 d 1 = v ⋅ 2 = 2 v
Car B: 15 mph faster than car A v 2 = v 1 + 15 t 2 = 1.5 d 2 = ( v 1 + 15 ) ⋅ 1.5 = 1.5 v 1 + 22.5
Both cars traveled equal distances: d 1 = d 2 2 v 1 = 1.5 v 1 + 22.5 2 v 1 − 1.5 v 1 = 22.5 0.5 v 1 = 22.5 v 1 = 45 v 2 = 45 + 15 = 60
Car B traveled at the speed of 60 mph.
Car B traveled at a speed of 60 mph. This was determined by calculating the speeds of both cars based on the equal distance they traveled in different times. Car A traveled at 45 mph, making Car B 15 mph faster.
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