Justin has [tex]3x + 12[/tex] songs. Jim has [tex]5x - 4[/tex] songs. If they both have the same number of songs, how many songs do they each have?

according to the quesiton;
3x + 12 = 5x -4 12 + 4 = 5x - 3x 16 = 2x 16 / 2 = x 8 = x x = 8
Now, substituting the value of "x" in one of the equation, we get, 3x + 12 = 3 (8) + 12 = 24 + 12 = 36
5x- 4 = 36 ...........because according to the question, 3x + 12 = 5x - 4
**So, each of them have 36 songs **

Answered by rabinshrestha41 | 2024-06-10

∗ J u s t i n ′ s so n g s − 3 x + 12 J i m ′ s so n g s − 5 x − 4 T h e s am e am o u n t so : 3 x + 12 = 5 x − 4 ∣ S u b t r a c t 3 x 12 = 2 x − 4 ∣ A dd 4 16 = 2 x ∣ D i v i d e b y 2 x = 8 3 x + 12 = 3 ∗ 8 + 12 = 24 + 12 = 36 5 x − 4 = 5 ∗ 8 − 4 = 40 − 4 = 36 J u s t in ha s 36 so n s an d J im ha s a l so 36 so n g s .

Answered by luana | 2024-06-10

Justin and Jim both have 36 songs. By setting their equations equal, we found that x = 8 allows us to calculate their song totals. Checking both equations confirms that their song counts are the same.
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Answered by rabinshrestha41 | 2024-12-26