1. Simplify: \((2xy^2)(-3x^2y)\)

2. Simplify: \(\left(\frac{1}{3}x^2y\right)(-9xy^3)\)

1) \ 2xy^2* (-3x^2y)\to \boxed{-6x^3y^3} \\\\\\ 2) \ \frac{1}{3x^2y}*(-9xy^3)= \frac{1}{x}*(-3y^2})\to\boxed{-\frac{3y^2}{x}}

Answered by mariamikayla | 2024-06-10

Multiply the numbers and letters... Let's separate them...
2 * -3 = -6 x * x^2 (add your exponents) = x^(1+2) = x^3 y^2 * y (add exp) = y^(2+1) = y^3
Put it all together!
-6x^3y^3
Do the same for no. 2.
(1/3)*-9 = -9/3 = -3 x^2 * x = x^(2+1) = x^3 y * y^3 = y^(1+3) = y^4
Put it together...
-3x^3y^4

Answered by scarlettears102 | 2024-06-10

The simplified result for the first expression is − 6 x 3 y 3 , and for the second expression, it is − 3 x 3 y 4 .
;

Answered by mariamikayla | 2024-11-04