Find the absolute value of [tex]9.8[/tex] and [tex]-\frac{10}{3}[/tex].

The absolute value of 9.8 is 9.8. The absolute value of -10/3 is found by using your order of operations like so: -10÷3= -3.333... l-3.333...l = 3.333...

Answered by Anonymous | 2024-06-10

By definition, the absolute value of a number is given by: ∣ a ∣ = a Where, The number a is a real number. This means that the value of a is both negative and positive. The result is always greater than zero. Therefore, the absolute value of the given numbers is given by: ∣9.8∣ = 9.8 ∣ − 3 10 ​ ∣ = 3 10 ​ **Answer: ****the absolute value of 9.8 and of -10/3 is: ** ∣9.8∣ = 9.8 ∣ − 3 10 ​ ∣ = 3 10 ​

Answered by carlosego | 2024-06-11

The absolute value of 9.8 is 9.8, and the absolute value of -10/3 is 10/3. We find the absolute value by determining the distance from zero, ignoring the sign. So, |9.8| = 9.8 and |-\frac{10}{3}| = \frac{10}{3}.
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Answered by carlosego | 2024-09-12