Assuming that no row can have a combination of black and white chairs, there will be 11 rows, each consisting of 10 chairs. 5 of these rows will have black chairs, and 6 of these rows will have white chairs. I arrived at this by finding the GCF (or greatest common multiple) of 50 and 60, which is 10. That number represents the maximum number of chairs per row. Then, I added 50 and 60, to get 110, and divided that by the number of chairs per row, 10, to arrive at there being 11 rows. 50/110 chairs are black, meaning 5 rows are black, and 60/110 chairs are white, meaning 6 rows are white. Hope this helps! ~ArchimedesEleven
the factors of 60 are 1,2,3,5,6,10,12,20,30,and 60 the factors of 50 are 1,2,5,10,15,and 30 so the GCF is 10
Bryan can fit a maximum of 10 chairs in each row. He will have 5 rows of black chairs and 6 rows of white chairs, making a total of 11 rows. This arrangement uses all of his chairs efficiently.
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