HotelInfantesAgres - Together we solve school questions. Logo

In Mathematics / Middle School | 2014-10-03

The length of a rectangle is 8 inches more than its width. The perimeter is 52 inches.

What is the length of the rectangle?

Asked by Soph88

Answer (3)

L = w + 8 P = 2 L + 2 w P = 52 in 2 ( w + 8 ) + 2 w = 52 2 w + 16 + 2 w = 52 4 w = 52 − 16 4 w = 36 w = 4 36 ​ = 4 in ​ L = 4 + 8 L = 12 in ​

Answered by mariamikayla | 2024-06-10

It would be 17 for the length And 9 for the width

Answered by booner | 2024-06-10

The length of the rectangle is 17 inches. We calculated the width to be 9 inches first, then applied it to find the length. Therefore, the final dimensions we found are consistent with the perimeter given in the problem.
;

Answered by mariamikayla | 2024-12-26

Related Questions in Mathematics

[Homework Help] Select the correct answer. Which equation is equivalent to the given equation? [tex]$x^2-6 x=8$[/tex] A. [tex]$(x-6)^2=44$[/tex] B. [tex]$(x-3)^2=17$[/tex] C. [tex]$(x-6)^2=20$[/tex] D. [tex]$(x-3)^2=14$[/tex]

[Homework Help] Which phrase best describes the translation from the graph [tex]y=6 x^2[/tex] to the graph of [tex]y=6(x+1)^2[/tex]? A. 6 units left B. 6 units right C. 1 unit left D. 1 unit right

[Homework Help] What expression is equivalent to [tex]$\left(5 z^2+3 z+2\right)^2$[/tex] ? A. [tex]$5 z^4+3 z^2+4$[/tex] B. [tex]$5 z^4+9 z^2+4$[/tex] C. [tex]$25 z^4+30 z^3+19 z^2+12 z+4$[/tex] D. [tex]$25 z^4+30 z^3+29 z^2+12 z+4$[/tex]

[Homework Help] The graph of [tex]y=\frac{5}{4} x+1[/tex] is shown below. The coordinate ([tex]0, y[/tex]) is a solution of the equation. Given the [tex]x[/tex]-value of 0, what is the value of the [tex]y[/tex]-coordinate for the coordinate ([tex]0, y[/tex])? [tex]y=[/tex] [blank]

[Homework Help] If [tex]f(-2)=0[/tex], what are all the factors of the function [tex]f(x)=x^3-2 x^2-68 x-120[/tex]? Use the Remainder Theorem. A. [tex](x+2)(x+60)[/tex] B. [tex](x-2)(x-60)[/tex] C. [tex](x-10)(x+2)(x+6)[/tex] D. [tex](x+10)(x-2)(x-6)[/tex]