How do I solve the equation \(3k - 1 = 7k + 2\) and similar problems?

You do whatever you need to do in order to get ' k ' all by itself on one side of the equation,and everything else on the other side. BUT ... remember that whatever you do to one side of the equation, you must also do the same thing to the other side.
3k - 1 = 7k + 2
Here's one way to do it:
Subtract 2 from each side: 3k - 3 = 7k
Subtract 3k from each side: -3 = 4k
Divide each side by 4 : *** - 3/4 = k***

Answered by AL2006 | 2024-06-10

To solve problems like this we have to have only one variable on LHS.
So 3k-1=7k+2 /-2 both side 3k-3=7k / -3k both side -3=4k /:4 divide by 4 both siede 4 − 3 ​ = k And know we can change sides. k= 4 − 3 ​

Answered by macio06 | 2024-06-10

To solve the equation 3 k − 1 = 7 k + 2 , first isolate the variable by moving constants to one side and variable terms to the other. Then divide by the coefficient of the variable to find k . Always check your solution by substituting the value back into the original equation.
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Answered by AL2006 | 2024-12-26