Container A and B hold 11,875 liters of water altogether. Container B holds 2,391 liters more than Container A. How much water does Container A hold?

To find the answer we have to create system of equation and substitute b from second eq to the first. { a + 2391 = b a + b = 11875 ​ a + a + 2391 = 11875 Now we have to solve eq 2a+2391=11875 /-2391 both sides 2a=9484 /:2 a=4742 Now we can back substitute to second eq and find value of b b=4742+2391 b=7133 Its the result { b = 7133 a = 4742 ​

Answered by macio06 | 2024-06-10

Container A holds 4742 liters of water. Container B holds 7133 liters of water. Together, they hold a total of 11875 liters with Container B holding 2391 liters more than Container A.
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Answered by macio06 | 2024-12-26