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In Mathematics / Middle School | 2014-10-01

A decimal number has 2 digits to the right of its decimal point. If we round it to the nearest tenth, the result is 18.6. What is the maximum possible value of this decimal?

Asked by leah1126

Answer (2)

The maximum possible value of the decimal number before rounding to the nearest tenth and resulting in 18.6 is 18.649.
The maximum possible value of a decimal number which rounds to 18.6 to the nearest tenth can be determined using the rounding rules. When a number is rounded to the nearest tenth, the hundredths place determines if the tenths place is rounded up or remains the same. Since 18.6 is the rounded figure, the largest number it could have been before rounding would be anything up to 18.649, as rounding 18.650 and above would result in 18.7. so the correct answer is 18.649
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Answered by JohnRogerStephens | 2024-06-24

The maximum possible value of a decimal number that rounds to 18.6 is 18.649. This is because it must be less than 18.65, which would round up to 18.7. Therefore, 18.649 is the largest number that rounds down to 18.6.
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Answered by JohnRogerStephens | 2024-12-26