Suma a trei numere este 3932.

Primul număr este cu 1330 mai mare decât al doilea și cu 1740 mai mare decât al treilea.

Determinați cele trei numere.

a+b+c= 3932
a=b+1330 a=c+1740 ⇒c=a-1740⇒c=(b+1330)-1740
Obt.
b+1330 +b+(b+1330)-1740=3932 ⇒3b+2660-1740=3932⇒3b+920=3932⇒3b=3932-920⇒3b=3012⇒b=3012/3⇒ b = 1004 ​
a=b+1330⇒a=1004+1330⇒ a = 2334 ​
c=a-1740⇒c=23334-1740⇒ c = 594 ​

Answered by tsorin99 | 2024-06-10

The three numbers are 2334, 1004, and 594. The first number is 2334, the second is 1004, and the third is 594, maintaining the conditions of their relationships. The sum of these three numbers equals 3932.
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Answered by tsorin99 | 2024-11-01