A company charges $46 for cable TV installation and $21 per month for basic cable service.
Write an algebraic expression to represent the total cost of \(m\) months of basic cable service, including installation.
Answer (2)
46$ f or c ab l e 21$ p er m o n t h s m − am o u n t o f m o n t h s t o t a l cos t = 46 + 21 ∗ m o n t h s f ( m ) = 46 + 21 m
The algebraic expression for the total cost of cable TV installation and service is T ( m ) = 46 + 21 m , where m is the number of months. This includes a one-time installation fee of $46 and a monthly service charge of $21. Thus, as the number of months increases, the total cost increases linearly based on the monthly fee.
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