Explain why numbers with a 5 in the ones place are not prime numbers.

In order for a number to be a prime number, it must only be divisible by 1 and itself. Just like any number that is even can be divisible by 2, any number that ends in 0 or 5 can be divisible by 5. So that is why a number that ends in 5 is not prime, because it has another factor other than 1 and itself, and that would be 5. Hope this helped! :D

Answered by TicTacManiac64 | 2024-06-10

The number with 5 in one place are not prime numbers .
Given that, A statement is to justify that **numbers **with a 5 in one place are not prime numbers .
What is a number system?
A number **system **is described as a technique of composing to represent digits. It is the mathematical inscription for describing numbers of a given set by using numbers or other characters in a uniform method. It delivers a special presentation of every **digit **and describes the arithmetic structure .
Here, Since, the property of a **prime number **is it can be divisible by 1 or itself since 5 is a prime number but double digits or further with number 5 on the one place are not the prime number because they will be divided by 5.
Thus, the number with 5 in one place are not prime numbers .
Learn more about the **number system **here:
https://brainly.com/question/22046046
#SPJ2

Answered by priyankapandeyVT | 2024-06-16

Numbers with a 5 in the ones place (other than 5 itself) cannot be prime because they are divisible by 5. A prime number can only be divided by 1 and itself, and having a 5 in the ones place guarantees additional divisors. Thus, only the number 5 is prime in this category; all other numbers with a 5 at the end are not prime.
;

Answered by priyankapandeyVT | 2024-09-26