Write 42 and 63 as products of their prime factors.
Answer (2)
42∣2 21∣3 . 7∣7 . 1∣ 42 = 2 × 3 × 7 63∣3 21∣3 . 7∣7 . 1∣ 63 = 3 × 3 × 7
The prime factorization of 42 is 2 multiplied by 3 and 7 (2 × 3 × 7). The prime factorization of 63 is 3 squared multiplied by 7 (3² × 7). Therefore, 42 = 2 × 3 × 7 and 63 = 3² × 7.
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